
M Question 1 |
⏱ 0 |
Sum of the two-digit number is 8 and when digits of the two-digit number are interchanged the new number is 18 more than the original. If original number is P, then consider the following statement: Statement I: P is a prime number. Statement II: P + 14 = Q2 and Q is divisible by 2 and 7. Which of the following statement is correct? (a) Only Statement I (b) Only Statement II (c) Both Statement I and II (d) Neither Statement I nor II | |
Correct Answer : Option d
ExplanationLet the two-digit number be P = 10a + b, where a and b are the tens and unit’s digits respectively.
Given that the sum of the digits is 8, so a + b = 8.
Also, the number formed by interchanging the digits is 18 more than the original, so:
10b + a = P+18 = 10a + b + 18
Simplifying:
10b + a = 10a + b + 18
10b – b + a − 10a = 18
b – a = 2
Now solve the system:
1. a + b = 8
2. b – a = 2
So, a = 3 and b = 5
Therefore, the original number P = 10a + b = 35
Now check the statements:
Statement I is incorrect as 35 is not a prime number (divisible by 5 and 7)
Statement II: P + 14 = 35 + 14 = 49, which is divisible by 7 but not by 2,
So, Statement II is also incorrect.
Hence, the correct option is d.
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